Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 13 - Section 13.2 - Using Trigonometric Ratios to Find Angles - Exercise - Page 546: 7

Answer

$$A=45°$$ $$B=45°$$

Work Step by Step

Find angle A. We can use the trigonometric function for tangent to find angle A. $tan A=\frac{a}{b}$ $tan A=\frac{29.7m}{29.7m}$ $tan A=1$ Now we solve for A by multiplying both sides of the equation by the inverse tangent. So, $tan^{-1}(tan A) = tan^{-1}(1)$ $A = tan^{-1}(1)$ $A=45°$ Find angle B. We know that in right triangles the sum of the acute angles is 90°. So, $A+B=90°$ Solving for $B$, we get $B=90°-A$ $B=90°-45°$ $B=45°$
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