Answer
$$A=38.1°$$
$$B=51.9°$$
Work Step by Step
Find angle A.
We can use the trigonometric function for sine to find angle A.
$sin A=\frac{a}{c}$
$sin A=\frac{25.45in}{41.25in}$
$sin A=0.6170$
Now we solve for A by multiplying both sides of the equation by the inverse sine.
So,
$sin^{-1}(sin A) = sin^{-1}(0.6170)$
$A = sin^{-1}(0.6170)$
$A=38.1°$
Find angle B.
We know that in right triangles the sum of the acute angles is 90°.
So, $A+B=90°$
Solving for $B$, we get
$B=90°-A$
$B=90°-38.1°$
$B=51.9°$
