Chapter 1 - Section 1.8 - Multiplication and Division of Fractions - Exercise - Page 49: 80

38 in

Work Step by Step

given the length of the each piece = 6$\frac{1}{8}$ in = $\frac{49}{8}$ in therefore total length of 6 pipes = 6 x$\frac{49}{8}$ in = $\frac{147}{4}$ in Given thickness of each plate = $\frac{1}{4}$ in therefore thickness of 5 plates = 5 x $\frac{1}{4}$ in = $\frac{5}{4}$ in therefore the overall length of the assembly = $\frac{147}{4}$ in + $\frac{5}{4}$ in = $\frac{152}{4}$ in = 38in

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