Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.8 - Multiplication and Division of Fractions - Exercise - Page 49: 80


38 in

Work Step by Step

given the length of the each piece = 6$\frac{1}{8}$ in = $\frac{49}{8}$ in therefore total length of 6 pipes = 6 x$\frac{49}{8}$ in = $\frac{147}{4}$ in Given thickness of each plate = $\frac{1}{4}$ in therefore thickness of 5 plates = 5 x $\frac{1}{4}$ in = $\frac{5}{4}$ in therefore the overall length of the assembly = $\frac{147}{4}$ in + $\frac{5}{4}$ in = $\frac{152}{4}$ in = 38in
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.