Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.8 - Multiplication and Division of Fractions - Exercise - Page 49: 68

Answer

22$\frac{2}{9}$ $ft^{3}$, 1333$\frac{1}{3}$ $ft^{3}$

Work Step by Step

given that 1$ft^{3}$ of cotton weigh 22$\frac{1}{2}$ lb convert 500 lb cotton into $ft^{3}$ = 500 $\div$ 22$\frac{1}{2}$ lb =500 $\div$ $\frac{45}{2}$ lb = 500 x $\frac{2}{45}$ = $\frac{200}{9}$$ft^{3}$ = 22$\frac{2}{9}$ $ft^{3}$ 1 ton = 2000 lb 15 ton = 15 x 2000 = 30000 lb convert 30000 lb cotton into $ft^{3}$ = 30000 $\div$ 22$\frac{1}{2}$ lb =30000 $\div$ $\frac{45}{2}$ lb = 30000 x $\frac{2}{45}$ = $\frac{4000}{3}$$ft^{3}$ = 1333$\frac{1}{3}$ $ft^{3}$
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