## Elementary Technical Mathematics

7$\frac{1}{4}$ft
We have equally spaced 19 ceiling outlets, the number of blank spaces will be 18 The distance between the first and last outlet is 130$\frac{1}{2}$ ft therefore the length of the distance between the ceiling outlet will be 130$\frac{1}{2}$ ft $\div$ 18 =$\frac{261}{2}$ $\div$ 18 = =$\frac{261}{2}$ x =$\frac{1}{18}$ ==$\frac{29}{4}$ =7$\frac{1}{4}$ft