## Elementary Technical Mathematics

2 $\frac{2}{3}$ $ft^{3}$
A concrete pad for mounting a condensing unit is of length 4ft, width is 2$\frac{2}{3}$ ft and thickness = $\frac{1}{4}$ ft Volume = lwh = 4 ft x 2$\frac{2}{3}$ ft x $\frac{1}{4}$ ft = 4 x $\frac{8}{3}$ x $\frac{1}{4}$ = $\frac{8}{3}$ =2 $\frac{2}{3}$ $ft^{3}$