# Chapter 1 - Section 1.8 - Multiplication and Division of Fractions - Exercise: 52

a.) 12 pins b.) 11$\frac{29}{41}$ or 11 pins

#### Work Step by Step

Total length of the rod = 2 ft 6 in = 2 x 12 + 6 = 30 in. Number of pins we get after cutting into equal pieces of 2$\frac{1}{2}$ in = 30 in $\div \frac{5}{2}$ = 30 $\times \frac{2}{5}$ = 12 pins b.) lets take $\frac{1}{16}$ in waste in each pin so total pin length = 2$\frac{1}{2}$ in + $\frac{1}{16}$ = $\frac{5}{2} + \frac{1}{16}$ = $\frac{41}{16}$ therefore total number of pins = 30 $\times \frac{16}{41}$ = $\frac{480}{41}$ =11$\frac{29}{41}$ or 11 pins

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