Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.8 - Multiplication and Division of Fractions - Exercise - Page 48: 36


a)$23\frac{3}{4}$ square feet b)$20\frac{1}{6}$feet

Work Step by Step

a) To find the area, make use of the formula given in the question: Area = Length $\times$ Width In order to facilitate the easy multiplication of mixed fractions, first convert them to improper fractions. Convert them back to proper fractions after multiplication when presenting the answer. $= 6\frac{1}{3}\times3\frac{3}{4}$ $=\frac{19}{3}\times\frac{15}{4}$ $=\frac{95}{4}$ $=23\frac{3}{4}$ Square Feet b) Perimeter is found by adding all the lengths of all the sides. In this question, for easier adding of fractions we first convert them to improper fractions of the same denominater before adding. Perimeter = $6\frac{1}{3}\times2+3\frac{3}{4}\times2$ $=\frac{19}{3}\times2+\frac{15}{4}\times2$ $=\frac{38}{3}+\frac{30}{4}$ $=\frac{76}{6}+\frac{45}{6}$ $=\frac{121}{6}$ $=20\frac{1}{6}$feet
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