## Elementary Technical Mathematics

8$\frac{5}{8}$ in
Number of cuts = 3 +2+6+1 = 12 cuts Total length of the pieces, 3 x 2$\frac{1}{8}$ = 3 x $\frac{17}{8}$ = $\frac{51}{8}$ in 2 x 5$\frac{3}{4}$ = 2 x $\frac{23}{4}$ = $\frac{46}{4}$in 6 x $\frac{7}{8}$ = $\frac{42}{8}$in 1 x 3$\frac{1}{2}$ = 1 x $\frac{7}{2}$ = $\frac{7}{2}$in 12 x $\frac{1}{16}$ = $\frac{3}{4}$in Remaining length = 36in - $\frac{51}{8}$ in- $\frac{46}{4}$in - $\frac{42}{8}$in - $\frac{7}{2}$in - $\frac{3}{4}$in = 36in - $\frac{93}{8}$ in- $\frac{49}{4}$in - $\frac{7}{2}$in = $36 \times$ $\frac{8}{8 }$ - $\frac{93}{8}$ - $\frac{49}{4}\times$ $\frac{2}{2}$ - $\frac{7}{2}\times$ $\frac{4}{4}$ =$\frac{288}{8}$ - $\frac{93}{8}$ - $\frac{98}{8}$ - $\frac{28}{8}$ =$\frac{69}{8}$ =8$\frac{5}{8}$ in