## Elementary Technical Mathematics

$18.5\text{ inches}$
There are eight $2\frac{5}{16}$-inch spaces between the first and last rivets. Thus, the distance between the first and last rivets is: $\require{cancel} =8 \times 2\frac{5}{16} \\=8 \times \frac{16(2)+5}{16} \\=8 \times \frac{37}{16} \\=\cancel{8} \times \frac{37}{\cancel{16}2} \\=\frac{37}{2} \\=18.5\text{ inches}$