## Elementary Technical Mathematics

Published by Brooks Cole

# Chapter 1 - Section 1.8 - Multiplication and Division of Fractions - Exercise - Page 48: 48

#### Answer

$18.5\text{ inches}$

#### Work Step by Step

There are eight $2\frac{5}{16}$-inch spaces between the first and last rivets. Thus, the distance between the first and last rivets is: $\require{cancel} =8 \times 2\frac{5}{16} \\=8 \times \frac{16(2)+5}{16} \\=8 \times \frac{37}{16} \\=\cancel{8} \times \frac{37}{\cancel{16}2} \\=\frac{37}{2} \\=18.5\text{ inches}$

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