Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set: 86

Answer

$13x\sqrt[3]{6x}$

Work Step by Step

$x\sqrt[3]{48x}+11\sqrt[3]{6x^4}$ Factor out perfect cubes. $x\sqrt[3]{(8)(6)(x)}+11\sqrt[3]{6x^3x}$ Simplify. $x(2)\sqrt[3]{6x}+11(x)\sqrt[3]{6x}$ $2x\sqrt[3]{6x}+11x\sqrt[3]{6x}$ Add like radicals. $13x\sqrt[3]{6x}$
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