## Introductory Algebra for College Students (7th Edition)

$13x\sqrt[3]{6x}$
$x\sqrt[3]{48x}+11\sqrt[3]{6x^4}$ Factor out perfect cubes. $x\sqrt[3]{(8)(6)(x)}+11\sqrt[3]{6x^3x}$ Simplify. $x(2)\sqrt[3]{6x}+11(x)\sqrt[3]{6x}$ $2x\sqrt[3]{6x}+11x\sqrt[3]{6x}$ Add like radicals. $13x\sqrt[3]{6x}$