#### Answer

$\sqrt[3]2$

#### Work Step by Step

$3\sqrt[3]{54}-4\sqrt[3]{16}$
Factor out perfect cubes.
$3\sqrt[3]{(27)(2)}-4\sqrt[3]{(8)(2)}$
Simplify.
$3(3)\sqrt[3]{2}-4(2)\sqrt[3]{2}$
$9\sqrt[3]2-8\sqrt[3]2$
Add like radicals.
$\sqrt[3]2$

Published by
Pearson

ISBN 10:
0-13417-805-X

ISBN 13:
978-0-13417-805-9

$\sqrt[3]2$

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