## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set - Page 592: 69

#### Answer

$5$

#### Work Step by Step

RECALL: (i) $(a+b)(a-b) = a^2-b^2$ (ii) $\sqrt{a}^2=a, a \ge0$ Use rule (i) above to obtain: $=\sqrt{10}^2-\sqrt{5}^2$ Use rule (ii) above to obtain: $=10-5 \\=5$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.