Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set - Page 592: 62

Answer

$\sqrt{10}-8\sqrt{5}+3\sqrt{2}-24$

Work Step by Step

$(\sqrt{5}+3)(\sqrt{2}-8)$ Use the FOIL method to multiply the binomial. Multiply the First terms, the Outside terms, the Inside terms, and the Last terms. $(\sqrt{5}\times\sqrt{2})+(-8\times\sqrt5)+(3\times\sqrt2)+(3\times(-8))$ Simplify. $\sqrt{10}-8\sqrt{5}+3\sqrt{2}-24$
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