Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Mid-Chapter Check Point: 9

Answer

$2x^3\sqrt{3x}$

Work Step by Step

$\sqrt{6x^3}\times\sqrt{2x^4}$ Use the product rule for square roots. $\sqrt{12x^7}$ Factor out perfect squares. $\sqrt{(4x^6)(3x)}$ Simplify. $2x^3\sqrt{3x}$
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