## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 8 - Mid-Chapter Check Point: 9

#### Answer

$2x^3\sqrt{3x}$

#### Work Step by Step

$\sqrt{6x^3}\times\sqrt{2x^4}$ Use the product rule for square roots. $\sqrt{12x^7}$ Factor out perfect squares. $\sqrt{(4x^6)(3x)}$ Simplify. $2x^3\sqrt{3x}$

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