Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Mid-Chapter Check Point: 7

Answer

$2\sqrt{15}-30$

Work Step by Step

$\frac{\sqrt5}{2}(4\sqrt3-6\sqrt{20})$ Use the distributive propety. $\frac{\sqrt5}{2}(4\sqrt3)-\frac{\sqrt5}{2}(6\sqrt{20}))$ Use the product rule for square roots. $\frac{4\sqrt{15}}{2}-\frac{6\sqrt{100}}{2}$ Simplify. $2\sqrt{15}-3(10)$ $2\sqrt{15}-30$
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