## Introductory Algebra for College Students (7th Edition)

$2x\sqrt2$
$\frac{\sqrt{56x^5}}{\sqrt{7x^3}}$ Rationalize the denominator. $\frac{\sqrt{56x^5}\times\sqrt{7x^3}}{\sqrt{7x^3}\times\sqrt{7x^3}}$ Use the product rule for square roots. $\frac{\sqrt{392x^8}}{7x^3}$ Factor out perfect squares. $\frac{\sqrt{(196)(2)x^8}}{7x^3}$ Simplify. $\frac{14x^4\sqrt{2}}{7x^3}$ Divide. $2x\sqrt2$