Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Mid-Chapter Check Point: 13

Answer

$2x\sqrt2$

Work Step by Step

$\frac{\sqrt{56x^5}}{\sqrt{7x^3}}$ Rationalize the denominator. $\frac{\sqrt{56x^5}\times\sqrt{7x^3}}{\sqrt{7x^3}\times\sqrt{7x^3}}$ Use the product rule for square roots. $\frac{\sqrt{392x^8}}{7x^3}$ Factor out perfect squares. $\frac{\sqrt{(196)(2)x^8}}{7x^3}$ Simplify. $\frac{14x^4\sqrt{2}}{7x^3}$ Divide. $2x\sqrt2$
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