Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Mid-Chapter Check Point: 10

Answer

$2\sqrt[3]2$

Work Step by Step

$\frac{\sqrt[3]{32}}{\sqrt[3]2}$ Rationaize the denominator. $\frac{\sqrt[3]{32}\times\sqrt[3]2\times\sqrt[3]2}{\sqrt[3]2\times\sqrt[3]2\times\sqrt[3]2}$ Use the product rule for nth roots. $\frac{\sqrt[3]{128}}{2}$ Factor out perfect cubes. $\frac{\sqrt[3]{(64)(2)}}{2}$ Simplify. $\frac{4\sqrt[3]{2}}{2}$ $2\sqrt[3]2$
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