Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.4 - Polynomials in Several Variables - Exercise Set: 61

Answer

$9x^2y^4-16y^2$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the product of the given expression, $ (3xy^2-4y)(3xy^2+4y) ,$ is \begin{array}{l}\require{cancel} (3xy^2)^2-(4y)^2 \\\\= 9x^2y^4-16y^2 .\end{array}
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