Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.4 - Polynomials in Several Variables - Exercise Set: 47

Answer

$x^2y^2-6xy+9$

Work Step by Step

Using $(a\pm b)^2=a^2\pm2ab+b^2$ or the square of a binomial, the square of the given expression, $ (xy-3)^2 ,$ is \begin{array}{l}\require{cancel} (xy)^2-2(xy)(3)+(3)^2 \\\\= x^2y^2-6xy+9 .\end{array}
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