Answer
$x^4-4x^2y^2+4y^4$
Work Step by Step
Using $(a\pm b)^2=a^2\pm2ab+b^2$ or the square of a binomial, the square of the given expression, $
(x^2-2y^2)^2
,$ is
\begin{array}{l}\require{cancel}
(x^2)^2-2(x^2)(2y^2)+(2y^2)^2
\\\\=
x^4-4x^2y^2+4y^4
.\end{array}