Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.4 - Polynomials in Several Variables - Exercise Set: 43

Answer

$15x^{2}y^{2}+xy-2 $

Work Step by Step

Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $ (3xy-1)(5xy+2) ,$ is \begin{array}{l}\require{cancel} 3xy(5xy)+3xy(2)-1(5xy)-1(2) \\\\= 15x^{1+1}y^{1+1}+6xy-5xy-2 \\\\= 15x^{2}y^{2}+6xy-5xy-2 \\\\= 15x^{2}y^{2}+xy-2 .\end{array}
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