Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by the Substitution Method - Exercise Set - Page 300: 6



Work Step by Step

x+2y=5 x+2y-2y=5-2y x=5-2y Plug this value for x into the other equation. 2x-y=-15 2(5-2y)-y=-15 2(5)-2(2y-y)=-15 10-5y=-15 -5y=-15-10 -5y=-25 y=$\frac{-25}{-5}$ y=5 Plug this back into the first equation to find x. x=5-2y x=5-2(5) x=5-10 x=-5 Therefore the solution is {(-5,5)}
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