Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by the Substitution Method - Exercise Set - Page 300: 5



Work Step by Step

x+3y=5 x+3y-3y=5-3y x=5-3y Plug this value for x into the other equation. 4(5-3y)+5y=13 4(5)-4(3y)+5y=13 20-12y+5y=13 20-7y=13 -7y=13-20 -7y=-7 y=$\frac{-7}{-7}$ y=1 Plug this back into the first equation to find x x=5-3(1) x=5-3 x=2 Therefore the solution is {(2,1)}
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