## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by the Substitution Method - Exercise Set - Page 300: 20

#### Answer

{($\frac{18}{7}$,$\frac{8}{7}$)}

#### Work Step by Step

2x-y=4 2x-2x-y=4-2x -y=4-2x -1(-y)=-1(4-2x) y=-4+2x Plug this value for y into the other equation. 3x-5(-4+2x)=2 3x-5(-4)-5(2x)=2 3x+20-10x=2 3x-10x+20=2 -7x+20=2 -7x+20-20=2-20 -7x=-18 x=$\frac{-18}{-7}$ x=$\frac{18}{7}$ Plug this value for x into the first equation to solve for y. y=-4+2($\frac{18}{7}$) y=-4+$\frac{36}{7}$ y=-$\frac{28}{7}$+$\frac{36}{7}$ y=$\frac{8}{7}$ Therefore the solution is {($\frac{18}{7}$,$\frac{8}{7}$)}

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.