#### Answer

{($\frac{14}{5}$,$\frac{1}{5}$)}

#### Work Step by Step

-4x+y=-11
y=-11+4x
Plug this value for y into the other equation.
2x-3y=5
2x-3(-11+4x)=5
2x-3(-11)-3(4x)=5
2x+33-12x=5
2x-12x=5-33
-10x=5-33
-10x=-28
x=$\frac{-28}{-10}$
x=$\frac{14}{5}$
Plug this back into the first equation to find y.
y=-11+4x
y=-11+4($\frac{14}{5}$)
y=-11+$\frac{56}{5}$
y=-$\frac{55}{5}$+$\frac{56}{5}$
y=$\frac{1}{5}$
Therefore the solution is {($\frac{14}{5}$,$\frac{1}{5}$)}