Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 3 - Section 3.3 - Slope - Exercise Set - Page 242: 43

Answer

$y=4$

Work Step by Step

Use: $m=\displaystyle \frac{\text{change in y}}{\text{change in x}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}.$ The product of slopes of perpendicular lines is $-1,\quad$ $(m_{1}=-\displaystyle \frac{1}{m_{2}} ).$ The slope of the line passing through $(2,3)$ and $(-2,1)$ is $m_{1}=\displaystyle \frac{1-3}{-2-2}=\frac{-2}{-4}=\frac{1}{2}$ The line passing through $(-1,y)$ and $(1,0)$ has the slope $m_{2}=\displaystyle \frac{0-y}{1-(-1)}=\frac{-y}{2}$ Since the lines are perpendicular, $m_{1}\cdot m_{2}=-1$ $\displaystyle \frac{1}{2}\cdot(\frac{-y}{2})=-1\qquad $... multiply with $-4$, $y=4$
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