Answer
perpendicular
Work Step by Step
m=$\frac{y_2-y_1}{x_2-x_1}$
m=$\frac{-15-(-3)}{-2-0}$
m=$\frac{-12}{-2}$
m=6
m=$\frac{y_2-y_1}{x_2-x_1}$
m=$\frac{6-3}{-12-6}$
m=$\frac{3}{-18}$
m=$\frac{1}{-6}$
m=-$\frac{1}{6}$
6$\times$-$\frac{1}{6}$=-1
Therefore the lines are parallel.