Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 3 - Section 3.3 - Slope - Exercise Set - Page 242: 42

Answer

$y=-6$

Work Step by Step

Use: $m=\displaystyle \frac{\text{change in y}}{\text{change in x}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}.$ Parallel lines have equal slopes. The slope of the line passing through $(-3,4)$ and $(-5,-2)$ is $m_{1}=\displaystyle \frac{-2-4}{-5-(-3)}=\frac{-6}{-2}=3$ The line passing through $(1,y)$ and $(7,12)$ has the slope $m_{2}=\displaystyle \frac{12-y}{7-1}=\frac{12-y}{6}$ Since the lines a re parallel, $m_{1}=m_{2}$ $\displaystyle \frac{12-y}{6}=3\qquad $... multiply with $6$, $12-y=18 \qquad $... add $y-18$ $12-18=y$ $y=-6$
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