Answer
$t=20.03$ years. thus, at year $2030$
Work Step by Step
$A=1173.1e^{0.008t}, A=1377$
$1377=1172.1e^{0.008t}$
$1.1738=e^{0.008t}$
$\ln 1.1738=0.008t$
$t=20.03$ years. thus, at year $2030$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 9 - Section 9.6 - Exponential Growth and Decay; Modeling Data - Exercise Set - Page 740: 5
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