Answer
$k=-0.0039$
Work Step by Step
$A=A_{0}e^{kt}$
For $A_{0}=82.3, A=70.5, t=40$
$70.5=82.3e^{40k}$
$0.8566=e^{40k}$
$\ln 0.8566=40k$
$k=-0.0039$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 9 - Section 9.6 - Exponential Growth and Decay; Modeling Data - Exercise Set - Page 740: 13
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