Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.6 - Exponential Growth and Decay; Modeling Data - Exercise Set - Page 740: 12

Answer

$k=0.0174$

Work Step by Step

$A=A_{0}e^{kt}$ For $A_{0}=21.3, A=42.7, t=40$ $42.7=21.3e^{40k}$ $2.0047=e^{40k}$ $\ln 2.0047=40k$ $k=0.0174$
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