Answer
$\frac{y^8}{16x^{12}}$
Work Step by Step
$(-2x^3y^{-2})^{-4}$
$=(-2)^{-4}(x^3)^{-4}(y^{-2})^{-4}$
$=\frac{1}{16} \times \frac{1}{x^{12}}\times y^8$
$=\frac{y^8}{16x^{12}}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set - Page 730: 149
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
