Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set - Page 730: 148

Answer

$x=-12$

Work Step by Step

$\frac{3}{x+1}-\frac{5}{x}=\frac{19}{x^2+x}$ $3x-5(x+1)=19$ $3x-5x-5=19$ $-2x=24$ $x=-12$
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