Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set - Page 730: 136

Answer

It doesn't make sense.

Work Step by Step

The statement doesn't make sense because we use different methods to solve the two equations. For $\log(3x+1)=5$ we use exponential form to solve for logarithmic equation: $3x+1=10^5$ $3x=99999$ $x=33333$ For $\log(3x+1)=\log5,$ we use one to one property of logarithms to solve since both sides of the equation is logarithmic equation with the same base: $3x+1=5$ $3x=4$ $x=\frac{4}{3}$
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