Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set - Page 727: 99

Answer

a. $A=37.3$ b. $t=7.32$ years, meaning in year $2018$

Work Step by Step

$A=37.3e^{0.0095t}$ a. At 2010, $t=0,$ Therefore, $A=37.3e^0=37.3$ b. $A=40$ $40=37.3e^{0.0095t}$ $1.072=e^{0.0095t}$ $\ln 1.072=0.0095t$ $t=7.32$ years, meaning in year $2018$
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