Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set: 51

Answer

$x=4\frac{1}{27}$

Work Step by Step

RECALL: $\log_b{x}= y \longrightarrow b^y=x$ Use the rule above to obtain: $3^{-3}=x-4 \\\dfrac{1}{3^3}=x-4 \\\dfrac{1}{27}=x-4$ Add $4$ on both sides of the equation to obtain: $4+\dfrac{1}{27}=x \\4\frac{1}{27}=x$
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