Answer
a.$A=25$ million
b.$t=6.06$ years later, meaning in year $2017$
Work Step by Step
$A=25e^{0.0187t}$
a. At $2010, t=0$
Thus, $A=25e^0=25$ million
b. $28=25e^{0.0187t}$
$1.12=e^{0.0187t}$
$\ln 1.12=0.0187t$
$t=6.06$ years later, meaning in year $2017$
