Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set - Page 727: 86

Answer

The solution set is $\{22\}$.

Work Step by Step

The given equation is $\log (x-2) + \log 5 = \log 100$ Use product rule. $\log (x-2)^5 = \log 100$ $ (x-2)^5 = 100$ Divide both sides by $5$. $ \frac{(x-2)5}{5} = \frac{100}{5}$ Simplify. $x-2 = 20$ Add $2$ to both sides $x-2+2=20+2$. Simplify. $x=22$.
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