Answer
$f^{-1}(x)=\sqrt[3] {\frac{x+7}{10}}$
Work Step by Step
$f(x)=10x^3-7$
$x=10y^3-7$
$x+7=10y^3$
$\sqrt[3] {\frac{x+7}{10}}=y$
$f^{-1}(x)=\sqrt[3] {\frac{x+7}{10}}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 9 - Mid-Chapter Check Point - Page 715: 6
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
