Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Mid-Chapter Check Point: 20

Answer

$-2$

Work Step by Step

Write $\frac{1}{9}$ as $\frac{1}{3^2}$ to obtain: $=\log_3{(\frac{1}{3^2})}$ Use the rule $\dfrac{1}{a^m} = a^{-m}$ to obtain: $=\log_3{(3^{-2})}$ RECALL: $\log_b{b^x} = x$ Use the rule above to obtain: $=-2$
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