Answer
$-2$
Work Step by Step
Write $\frac{1}{9}$ as $\frac{1}{3^2}$ to obtain:
$=\log_3{(\frac{1}{3^2})}$
Use the rule $\dfrac{1}{a^m} = a^{-m}$ to obtain:
$=\log_3{(3^{-2})}$
RECALL:
$\log_b{b^x} = x$
Use the rule above to obtain:
$=-2$
