Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Mid-Chapter Check Point: 22

Answer

$\dfrac{1}{3}$

Work Step by Step

Use the rule $\sqrt[3]{a}= a^{\frac{1}{3}}$ to obtain: $=\log{(10^{\frac{1}{3}})}$ RECALL: $\log_b{b^x} = x$ Use the rule above to obtain: $=\dfrac{1}{3}$
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