Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Mid-Chapter Check Point - Page 715: 29

Answer

$\sqrt{\pi}$

Work Step by Step

RECALL: $\log_b{(b^x)}=x$ Use the rule above with $b=\pi$ to obtain: $\log_{\pi}{(\pi^{\sqrt{\pi}})}=\sqrt{\pi}$
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