## Intermediate Algebra for College Students (7th Edition)

$x=\pm \sqrt {6}$ or, $x=+\sqrt {6},-\sqrt {6}$
Given: $7x^2=42$ This can be written as: $x^2=\dfrac{42}{7}$ or, $x^2=6$ Apply The Square Root Property. $x=\sqrt{6}$ Hence, $x=\pm \sqrt {6}$ or, $x=+\sqrt {6},-\sqrt {6}$