Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.1 - The Square Root Property and Completing the Square - Exercise Set - Page 592: 18

Answer

{$5+2i,5-2i$}

Work Step by Step

Given: $(x-5)^2=-4$ Apply The Square Root Property. This can be written as: $x-5=\sqrt{-4}$ As we know that $\sqrt{-1}=i$] or, $x-5=\pm 2i$ or, $x=5+2i,5-2i$ Hence, solution set is $x=${$5+2i,5-2i$}
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