## Intermediate Algebra for College Students (7th Edition)

$x=+\dfrac{7}{2}i,-\dfrac{7}{2}i$
iven: $4x^2+49=0$ This can be written as: $4x^2=-49$ or, $x^2=-\dfrac{-49}{4}$ Apply The Square Root Property. $x=\pm \sqrt{-\dfrac{49}{4}}$ or, $x=\pm\sqrt{-1} \sqrt{\dfrac{49}{4}}$ Since, $\sqrt {-1}=i$ Thus, $x=\pm \dfrac{7}{2}i$ Hence, $x=+\dfrac{7}{2}i,-\dfrac{7}{2}i$