Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.1 - The Square Root Property and Completing the Square - Exercise Set - Page 592: 15


{$-2+2\sqrt 2,-2-2\sqrt 2$}

Work Step by Step

Given: $2(x+2)^2=16$ This can be written as: $(x+2)=8$ Apply The Square Root Property. or, $x+2=\sqrt{8}$ or, $x+2=\pm (2\sqrt 2)$ or, $x=-2+2\sqrt 2,-2-2\sqrt 2$ Hence, solution set is $x=${$-2+2\sqrt 2,-2-2\sqrt 2$}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.