Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set - Page 551: 125

Answer

$7+4\sqrt3$.

Work Step by Step

The given expression is $=(2+\sqrt3)^2$ Use the special formula. $(A+B)^2=A^2+2AB+B^2$ We have $A=2$ and $B=\sqrt3$. $=2^2+2(2)(\sqrt3)+(\sqrt3)^2$ Simplify. $=4+4\sqrt3+3$ $=7+4\sqrt3$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.