Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set - Page 551: 109


$\displaystyle \frac{7\sqrt{6}}{6}$

Work Step by Step

$\displaystyle \sqrt{\frac{1}{6}}=\frac{\sqrt{1}}{\sqrt{6}}=\frac{1}{\sqrt{6}}\color{red}{ \cdot\frac{ \sqrt{6}}{\sqrt{6}} }= \frac{\sqrt{6}}{6}$ $\displaystyle \sqrt{\frac{2}{3}}=\sqrt{\frac{4}{6}}=\frac{\sqrt{4}}{\sqrt{6}}=\frac{2}{\sqrt{6}}\color{red}{ \cdot\frac{ \sqrt{6}}{\sqrt{6}} }=\frac{2\sqrt{6}}{6}$ $\displaystyle \sqrt{6}-\sqrt{\frac{1}{6}}+\sqrt{\frac{2}{3}}= \frac{6\sqrt{6}}{6}- \frac{\sqrt{6}}{6}+ \frac{2\sqrt{6}}{6}$ $= \displaystyle \frac{7\sqrt{6}}{6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.