Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set - Page 551: 107

Answer

$-2\sqrt[3]{25}$

Work Step by Step

Rationalize $\displaystyle \frac{15}{ \sqrt[3]{5}}$ $\displaystyle \frac{15}{ \sqrt[3]{5}}\color{red}{ \cdot\frac{ \sqrt[3]{5^{2}}}{\sqrt[3]{5^{2}}} }=\frac{15\sqrt[3]{25}}{\sqrt[3]{5^{3}}}=\frac{15\sqrt[3]{25}}{5}=3\sqrt[3]{25}$ $3\sqrt[3]{25}-5\sqrt[3]{25}=-2\sqrt[3]{25}$
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